fs.is_exists
fs.is_exists
Function
Determine whether the path exists.
Syntax
fs(path).is_exists()
Parameters
No parameters.
Return value
| Type | Description |
|---|---|
| Bool | Returns true if the path exists, false otherwise. |
Example
file = fs('docs-exists.txt') file.write('BT') result = file.is_exists() // Output: true print result
Notes
- This method does not distinguish between files, directories or symbolic links.