# fs.is_symlink

## Function

Determine whether the path is a symbolic link.

## Syntax

```bt
fs(path).is_symlink()
```

## Parameters

No parameters.

## Return value

| Type | Description |
| ------ | ------ |
| Bool | Returns true if the link is a symbolic link, false otherwise. |

## Example

```bt
file = fs('demo.txt')
result = file.is_symlink()

// Output: false
print result
```

## Notes

- Returns false if the path does not exist.